2x^2+88x-81=0

Solution for 2x^2+88x-81=0 equation:

2x^2+88x-81=0

a = 2; b = 88; c = -81;
Δ = b2-4ac
Δ = 882-4·2·(-81)
Δ = 8392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8392}=\sqrt{4*2098}=\sqrt{4}*\sqrt{2098}=2\sqrt{2098}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-2\sqrt{2098}}{2*2}=\frac{-88-2\sqrt{2098}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+2\sqrt{2098}}{2*2}=\frac{-88+2\sqrt{2098}}{4}
$